简单题

直接枚举一个边的长度然后判断合不合法就好

注意正方形的情况

#include<iostream>
#include<cstdio>
#define int long long
using namespace std;
bool Test_MLE_start;
int T=1,n,ans=0,cnt=0;
inline int reads(){
	char c=getchar();
	int sum=0,f=1;
	while(!isdigit(c)){
		if(c=='-') f=-1;
		c=getchar();
	}
	while(isdigit(c)){
		sum=(sum<<3)+(sum<<1)+(c^'0');
		c=getchar();
	}
	return sum*f;
}
inline void files(){
	freopen("std.in","r",stdin);
	freopen("std.out","w",stdout);
}
inline void clr(){
//	Don't forget!

}
bool Test_MLE_end;
signed main(){
//	printf("%lf Mb\n",(&Test_MLE_end-&Test_MLE_start-1)/1024.0/1024.0);
//	files();
//	T=reads();
	while(T--){
		clr();
		n=reads();
		for(int i=1;i<=n/2+1;i++){
			int lst=n-(i*2);
			if(lst%2==0&&lst>0){
				if(lst/2!=i) ans++;
				if(lst/2==i) cnt++;
			}
		}
		ans/=2;
		ans*=6;
		ans+=cnt;
		printf("%lld\n",ans);
	}
	return 0;
}